A Mars rover traveled from point A to point B at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rover to travel at a speed of 2.5 cm/sec, and increased travel time by 15 minutes. What is the distance between point A and point B?

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5