Find the equations of a)The tangent
b)The normal
to the curve y=2x^3 - x^2 + 4x - 7 at the point where x = 1.

Given, equation of curve is

To find the intersection of given curve with X-axis, Put y = 0 in equation 1, we get,

x − 7 = 0 ⟹ x = 7

Thus, the curve cut the X-axis at (7,0).

Now, on differentiating equation of curve w.r.t. x, we get,

Next answer is in pic.

24 units

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.