Arectangular patio has a perimeter of 44 feet. if the length of the patio is 5 feet less than twice the width, find the dimensions of the patio.

ANSWER: L=13; W=9
--Please read this explanation and this will be much easier for you, it took time to type..

Set up variables first. I will lead through how to get the answer.

First get variables. So, what is Perimeter? Perimeter is like so:

P = 2L + 2W = 44ft
Now instead of using P, we'll continue with

2L + 2W = 44 because this can be used to help answer the question better than P.

"Length of the patio is 5 ft less than twice the width"

So it says "length of the patio", so we put

L =

"5 ft less than twice the width"

L = 2W - 5

Now we know what L is, and we can plug this in to our first equation!

2L + 2W = 44
L = 2W - 5

Multiply by 2...
2L = 4W - 10

Plug in...
4W - 10 (2L see?) + 2W = 44

Rearrange...
4W + 2W - 10 = 44

And solve...
=6W - 10 = 44
=6W = 44 + 10
=6W = 54
=6W/6 = 54/6
=W = 9

Now we have W. Plug this into our other equation.

L = 2W - 5
L = 2*9 - 5
L = 18 - 5
L = 13

The length of the patio is 13 ft and the width of the patio is 9 ft.

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