What is the equation of a line parallel to y=-3x+5 that passes through point (6, 8)

5y = 6x + 4

Step-by-step explanation:

from the given equation we have to calculate y-intercept and the slope.

y= -3x+5

when x=1

y=-3(1)+5

y=-3+5 = 2

.: slope = (y₂-y₁)/(x₂-x₁)

slope= (8-2)/(6-1)

slope= m= 6/5

now the intercept

y = mx+b

8 = (6/5)(6) +b

8=36/5 + b

b = 8 - 36/5

b = (8×5 - 36)/5

b= (40-36)/5

b = 4/5

.: the slope-intercept formula

y=mx+b

y=(6/5)x + 4/5

y = (6x +4)/5

5y = 6x+4

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

sorry i need the points

step-by-step explanation:

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