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Mathematics, 07.09.2021 18:40 haza1873

TJ solved a quadratic equation. His work is shown below, with Step 3 33 missing. What could TJ have written as the result from Step 3 33? 2 ( x + 6 ) 2 βˆ’ 5 = 45 2 ( x + 6 ) 2 = 50 Step 1 ( x + 6 ) 2 = 25 Step 2 Step 3 x = βˆ’ 11 or x = βˆ’ 1 Step 4 2(x+6) 2 βˆ’5 2(x+6) 2 (x+6) 2 x=βˆ’11 ​ =45 =50 =25 or x=βˆ’1 ​ Step 1 Step 2 Step 3 Step 4 ​

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TJ solved a quadratic equation. His work is shown below, with Step 3 33 missing. What could TJ have...
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