24.
Using suitable identity evaluate (998).
25. In figure - 5, if BE is bisector of ZABC and...
Mathematics, 31.08.2021 18:10 jacob7542
24.
Using suitable identity evaluate (998).
25. In figure - 5, if BE is bisector of ZABC and CE is bisector of ZACD, then show that
1
ZBEC = ZBAC .
Answers: 1
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