(ii) AD^2+CD^2=3(AM^2+DM^2)
Mathematics, 19.08.2021 14:30 lexigarwood
In rt. ∆ADC, if DM is the median, then:
(i) AD^2+CD^2=AM^2+DM^2
(ii) AD^2+CD^2=3(AM^2+DM^2)
(iii) AD^2+CD^2=2(AM^2+DM^2)
(iv) AD^2+CD^2=4(AM^2+DM^2)
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In rt. ∆ADC, if DM is the median, then:
(i) AD^2+CD^2=AM^2+DM^2
(ii) AD^2+CD^2=3(AM^2+DM^2)
(ii) AD^2+CD^2=3(AM^2+DM^2)
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