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The diagram shows the structure of a molecule of sulfur dioxide. The ratio of oxygen atoms in sulfur dioxide is always the same. How many oxygen atoms (O) are there when there are 6 sulfur atoms (S)? Explain how you got your answer.

Sulphur (iv) Oxide (SO₂)

In a single SO₂ Molecule... There's 2 oxygen atoms.

Now

If there a 6 molecules of SO₂

Quick Math

6 x 2 = 12.

Simply put...

THERE'S 12 OXYGEN ATOMS WHEN THERE'S 6 SULPHUR ATOMS.

Another way to look at it is

In SO₂

The ratio of Sulphur to Oxygen is 1:2

Meaning that the amount of Oxygen is double that of sulphur

Since the question stated "When there are 6 sulphur atoms"

It simply means that there's gonna be 12 Oxygen atoms.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

idk this answer sorry cant on this one.

step-by-step explanation: