f(x) = 6x / ( x^2 - 36)
f(x) = 6x / ( x-6)(x+6)
Since nothing cancels
The vertical asymptotes are when the denominator goes to zero
x-6 = 0 x+6=0
x=6 x= -6
Since the numerator has a smaller power than the denominator (1 < 2), there is an asymptote at y = 0
To find the zeros, we find where the numerator = 0
let's solve for y.
step 1: add 9x to both sides.
step 2: divide both sides by -2.
i dont know sorry