Determine X and Y
(2+i) (x+yi) = -7+3i​

x=-11\5+13\5i-iy

y=ix+(13\5+11\5i)

Step-by-step explanation:

x+yi=-7+3i\2+i

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=-11\5+13\5i

x=-11\5+13\5i-yi

x=-11\5+13\5i-iy

x+yi=\frac{-7+3i}{2+i}

x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}

x+yi=\frac{-11+13i}{5}

x+yi=-\frac{11}{5}+\frac{13}{5}i

yi=-\frac{11}{5}+\frac{13}{5}i-x

\frac{iy}{i}=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

y=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}

maybe - definition of supplementary angles. im not sure. sorry

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)