The shortest side of an isosceles triangle is labeled, in inches, in the triangle below. The two longer sides are 6 inches longer than the shortest side. The perimeter of the triangle is 33 inches.

Complete question is;

The shortest side of an isosceles triangle is 2x - 3 inches long. the longer sides are 6 inches longer than the shortest side. the perimeter of the triangle is 33 inches. what is the length of each side of the longer sides of the triangle.

Shortest side = 7 inches

Side 2 = 13 inches

Side 3 = 13 inches

Step-by-step explanation:

We are told that;

Triangle is isosceles

The shortest side is 2x - 3 inches

The other 2 sides which are equal because it's an isosceles triangle are both 6 inches longer than the shortest side. Thus;

Side 2 = side 3 = 2x - 3 + 6 = 2x + 3

Since perimeter = 33 and sum of all 3 sides is the perimeter. Thus;

(2x - 3) + 2x + 3 + 2x + 3 = 33

6x + 3 = 33

6x = 33 - 3

6x = 30

x = 30/6

x = 5

Thus;

Shortest side = 2(5) - 3 = 7

Other 2 sides are each; 2(5) + 3 = 13

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.