Mathematics, 19.07.2021 17:50 bleesedbeme

Consider the probability that at least 88 out of 153 registered voters will vote in the presidential election. Assume the probability that a given registered voter will vote in the presidential election is 63%. Approximate the probability using the normal distribution. Round your answer to four decimal places

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Answer from: dustonangiecook

0.9319 = 93.19% probability that at least 88 out of 153 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

153 voters:

This means that n = 153

Assume the probability that a given registered voter will vote in the presidential election is 63%.

This means that p = 0.63

Mean and standard deviation:

$\mu = E(X) = np = 153(0.63) = 96.39$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.63*0.37} = 5.97$

Consider the probability that at least 88 out of 153 registered voters will vote in the presidential election.

Using continuity correction, this is: $P(X \geq 88 - 0.5) = P(X \geq 87.5)$ , which is 1 subtracted by the p-value of Z when X = 87.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{87.5 - 96.39}{5.97}$

Z = -1.49

Z = -1.49 has a p-value of 0.0681.

1 - 0.0681 = 0.9319

0.9319 = 93.19% probability that at least 88 out of 153 registered voters will vote in the presidential election.

Answer from: Quest

idk bring the function back im not smart

step-by-step explanation:

Answer from: Quest

$m< xyz=\frac{1}{2}(a-b)$

$m< xoy=b$

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

$m< xyz=\frac{1}{2}(mayor\ arc\ xy-minor\ arc\ xy)$

substitute the values

$m< xyz=\frac{1}{2}(a-b)$

the measure of angle xoy is equal to

$m< xoy=minor\ arc\ xy$ > by central angle

substitute the value

$m< xoy=b$

Which equation is correct regarding the diagram of circle o? a) m∠xzy = (a + b)b) m∠xzy = (a – b)c)

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