A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting: F minimum

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

a)

b)

c)

Step-by-step explanation:

From the question we are told that:

Time

Frequency

Segments

Generally the equation for Frequency Range is mathematically given by

Therefore

a)

b)

c)

Generally the equation for Frequency Resolution is mathematically given by

Where

N=The Total dat points

N=Sampling Frequency *Time

Therefore

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

answer for #1 is c

answer for #2 is d

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