One bag of marbles contains 2 black , 3 red , and 5 white marbles . A second bag contains 3 white and 2 black marbles . What is the probability of selecting one marble from each bag and that they are not both black. Please help!!

NOT BOTH BLACK = 1-2/25 = 23/25

Step-by-step explanation:

Bag 1 : 8 non-black out of 10

P(1) = 8/10

Bag 2: 3 non-black out of 10

P(2)=3/5

Probability of both independent events happening can be calculated using the multiplication rule

P(1) and P(2) = P(1)*P(2) = 8/10 * 3/5 = 24/50 = 12/25 (both are not black, or none is black)

Interpretating not both black meaning at most one black, then

we calculate the probability of both are black,

P(1) = 2/10

P(2) = 2/5

Probability that both balls are black can be calculated using the multiplication rule

P(1) and P(2) = 2/10 * 2/5 = 2/25

Probability that NOT BOTH BLACK = 1-2/25 = 23/25, i.e. at most one black

answer: the first one

step-by-step explanation: use a calculator and divide the minutes by the dollars.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3