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Mathematics, 14.06.2021 06:20 kevinh2683

Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 cos(t), (15 βˆ’ t)(1 βˆ’ sin(t))> for 0 ≀ t ≀ 15 minutes, with x and y measured in meters. The derivatives of these functions are given by xβ€²(t) = 6 βˆ’ 2sin(t) and yβ€²(t) = βˆ’15cos(t) + tcos(t) βˆ’ 1 + sin(t).

1. Find the slope of the path at time t = 4. Show the computations that lead to your answer.

2. Find the time when the skier's horizontal position is x = 60.

3. Find the acceleration vector of the skier when the skier's horizontal position is x = 60.

4. Find the speed of the skier when he is at his maximum height and find his speed in meters/min.

5. Find the total distance in meters that the skier travels from t = 0 to t = 15 minutes.

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Part of a cross-country skier's path can be described with the vector function r = <2 + 6t + 2 co...
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