Complete the assignment on a separate sheet of paper

Please attach pictures of your work.

TO FIND :-

FORMULAES TO KNOW BEFORE SOLVING :-

SOLUTION :-

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

≈ 30.2

4x and 6y

im not sure though

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺