I(t)I, left parenthesis, t, right parenthesis models the daily solar irradiance, measured in \dfrac{\text{kWh}}{\text{m}^2\text{ -day}} m 2 -day kWh ​ start fraction, start text, k, W, h, end text, divided by, start text, m, end text, squared, start text, negative, d, a, y, end text, end fraction, on a farm, ttt days after the summer solstice. Here, ttt is entered in radians. I(t) = 1.5\cos\left(\dfrac{2\pi}{365}t\rig ht) + 4.3I(t)=1.5cos( 365 2π ​ t)+4.3I, left parenthesis, t, right parenthesis, equals, 1, point, 5, cosine, left parenthesis, start fraction, 2, pi, divided by, 365, end fraction, t, right parenthesis, plus, 4, point, 3 What is the second time after the summer solstice that the solar irradiance is 5.2 \dfrac{\text{kWh}}{\text{m}^2\text{ -day}}5.2 m 2 -day kWh ​ 5, point, 2, start fraction, start text, k, W, h, end text, divided by, start text, m, end text, squared, start text, negative, d, a, y, end text, end fraction? Round your final answer to the nearest whole day.

you never say the total so we cant find the percentage used for petrol

step-by-step explanation:

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.