A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer than four times its width. The width of play area B must be 2 feet longer than the width of play area A, and the length must be 2 feet longer than three times its own width. In addition, the areas of the two play areas must be equal. Write a system of equations to represent this situation, where y is the area of the play areas and x is the width of play area A. Which statement describes the number and viability of the system's solutions?

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

length of play area A

width of play area A

length of play area B

width of play area B

Area of A

Area of B

From the question, we have the following:

The area of A is:

This gives:

Open bracket

The area of B is:

Substitute:

Open brackets

Expand

We have that:

This gives:

Collect like terms

Using quadratic calculator, we have:

or --- approximated

But the width can not be negative; So:

idek

step-by-step explanation:

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.