Can you please do no 9? You will get a brainliest and 15 points of you help me with this question:P.

We know  , and cotA = 1/tanA, so tanA = 5/6, since we inverse 6/5 to 5/6.

Now we substitute the values in the expression tan(A + B) = (tanA + tanB) / (1 - tan(A) * tan(B)) as follows:

(5/6 + 1/11) / (1 - 5/6 * 1/11) = (61/66) / ((66-5)/66) = (61/66) / (61/66) = 1

So, tan(A + B) = 1, now we have to make A + B the subject of the formula, so we find the arctan of 1.

tan(A + B) = 1

(A + B) = arctan(1) or tan^-1(1)

(A + B) = 45 degress, which is the value of arctan(1) or tan^-1(1)

Therefore A + B = 45degrees.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer: b)

step-by-step explanation:

its a dot plot because since the score is not high numbers.

- r3ktforgood ☕