Use the information giving in the figure to find the length FH. If applicable, round your answer to the nearest whole number. The lengths on the figure are not drawn accurately.

9514 1404 393

  FH = 16

Step-by-step explanation:

ΔGHE is a 5-12-13 triangle.

ΔEHF is a 3-4-5 triangle with a scale factor of 4, so side FH is 4·4 = 16 units.

(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) are all commonly used Pythagorean triples. The first two on the list are used in these triangles.

If you like, you can work out the numbers using the Pythagorean theorem, which tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides.

For ΔEHG, that is ...

  GE² = EH² + HG²

  13² = EH² + 5²

  EH² = 13² -5² = 169 -25 = 144

And for ΔEHF, ...

  FE² = EH² +HF²

  20² = 144 + HF²

  400 -144 = HF² = 256

  HF = √256 = 16

The length of side FH is 16 units.

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)