Given a feedlot of about 2500 cows, if an individual cow produces about 40 liters of manure per day, how many kiloliters of manure would be produced in one month?​

9514 1404 393

  3000 kL

Step-by-step explanation:

  (2500 cows)(40 L/day/cow)(30 day/mo)(1 kL/(1000 L)) = 2.5×40×30 kL/mo

  = 3000 kL/mo

About 3000 kL of manure would be produced in one month.

___

That's about 3 cubic meters.

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;