Mrs. Garza polled 2 of her classes about their favorite dessert. The results are shown in the frequency table below.
Favorite
Dessert
Ice Cream
Cake
Pie
Pudding
Candy
Favorite Dessert
Frequency
Class 1
11
5
3
8
5
Frequency
Class 2
9
7
5
6
3
Which statement about the data represented in the table is true?
A
B
25% of Class 1 voted pudding as their favorite dessert.
Over 50% of Class 1 voted ice cream as their favorite dessert compared
to 9% of Class 2.
A total of 32 students were surveyed from Class 2.
40% of Class 2 voted for pudding as their favorite dessert.
с
D

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61

try soting them out first

step-by-step explanation:

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

-

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.