PLEASE HELP!!! The amount of polonium-210 remaining, P(t), after t days in a sample can be modeled by the exponential function P(t) = 100e−0.006t, where 100 represents the initial number of grams in the sample. What is an equivalent expression, written as a percentage rate of polonium-210 lost, and how much polonium-210 remains (rounded to the nearest whole number) after 16 days? Hint: Find the value of e−0.006 on your calculator. (7 points)

P(t) = 100e0.006t, 109 grams remain
P(t) = 100e0.994t, 3 grams remain
P(t) = 100(0.994)t, 91 grams remain
P(t) = 100(0.994)−t, 91 grams remain

the answer is b

70.30

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!