Me quickly
some thermodynamic properties of ethanol are listed in the table. thermodynamic properties property value c (solid) 0.5 j/g °c c (liquid) 1.0 j/g °c c (gas) 2.0 j/g °c melting point −114 °c boiling point 78 °c how much heat is released when 40.0 g of ethanol cools from −120 °c to −136 °c? 640 j 580 j 320 j 290 j question 5(multiple choice worth 3 points) (07.02 lc) if the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen? the 150 g al will reach a higher temperature. the 250 g al will reach a higher temperature. there will be no significant change in the temperature of either sample. both samples will reach the same final temperature.

Q1: 320 J.

Q2: The 150 g Al will reach a higher temperature.

Explanation:

Q1:

Q = m.c.ΔT.

where, Q is the amount of heat added or released,

m is the mass of the substance (m = 40.0 g),

c is the specific heat of the substance (c = 0.5 J/g.°C, the value of c of the solid ethanol, ethanol be solid at the temperature change mentioned).

ΔT is the temperature difference (final T - initial T) (ΔT = − 136 °C − (− 120 °C) = − 16 °C.

∴ Q = m.c.ΔT = (40.0 g)(0.5 J/g.°C)(− 16 °C) = − 320 J.

The negative sign means that the heat is released.

∴ The amount of heat is released when 40.0 g of ethanol cools from (−120 °C to −136 °C) = 320 J.

Q2:

Explanation:

Q = m.c.ΔT.

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).

∵ ΔT is inversely proportional to the mass of the substance.

∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).

So, the right choice is: The 150 g Al will reach a higher temperature.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2