The tables represent two linear functions in a system х
y
-6
-22
-3
-10
0
2
3
14
What is the solution to this system?
х
-6
-3
0
3
y
-30
-21
-12
-3
01-13-25)
0 (-34 -54)
O (-13, -50)
O (-14, -54)

(-14, -54)

Step-by-step explanation:

Let's call the functions f and g

f(x) = ax + b

f(0) = a*0+b = 2

f(3) = a*3 + b = 14

From f(0) = 2 we know that b = 2

f(3) - f(0) = a*3 = 14 - 2

a = 4

We know that f(x) = 4x + 2

g(x) = cx + d

g(0) = -12

g(3) = -3

From g(0) = -12 we know that d = -12

g(3) - g(0) = c*3 = -3 - (-12) = 9

c = 3

We know that g(x) = 3x - 12

Now we need to solve

4x + 2 = 3x - 12

x + 2 = -12

x = -14

y = 4*(-14) + 2 = -56 + 2 = -54

y = 3*(-14) - 12 = -42 - 12 = -54

Checks out.

(-5,-28)

i graphed to on desmos.