The temperature in jonestown and cooperville was the same at 1: 00. by 2: 00, the temperature in jonestown dropped 10 degrees, and the temperature in cooperville dropped 6 degrees. by 3: 00, the temperature in jonestown dropped 8 more degrees, and the temperature in cooperville dropped 2 more degrees.

a. write an equation that models the change to the temperature in jonestown since 1: 00.

b. write an equation that models the change to the temperature in cooperville since 1: 00.

c. where is it colder at 3: 00, jonestown or cooperville?

a). (x - 18)

b). (y - 8)

c). Jonestown will be cooler.

Step-by-step explanation:

A. Temperature in Jonestown and Cooperville was same at 1:00

By 2:00 the temperature in Jonestown dropped 10 degrees and by 3:00 dropped by 6 degrees.

Let the temperature at 1:00 was x°

Therefore, expression which represents the temperature drop will be

(x - 18)

B. In Cooperville drop in temperature was 6 degrees at 2:00 and 2 degrees at 3:00.

Let the temperature at 1:00 was y degrees

Therefore, expression which represents the temperature drop will be

(y - 8)

C. At 3:00, drop in temperature at Jonestown was (10 + 8) = 18 degrees and at Cooperville was (6 + 2) = 8 degrees

Therefore, Jonestown will be cooler.

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation: