Jklm is a rhombus. km is 6 and jl is 8. find the perimeter of the rhombus. image of rhombus jklm with diagonals jl and km intersecting at point n

If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.

The 2 diagonals of rhombus JKLM intersect at N.

Then m(MNJ)=90°,  |JN|=4 and |NM|=3 units

thus, by the Pythagorean theorem, 



The perimeter of the rhombus is 4*5 units=20 units.

20 units