A freight train has a mass of 1.1 ✕ 107 kg. If the locomotive can exert a constant pull of 8.1 ✕ 105 N, how long does it take to increase the speed of the train from rest to 60 km/h?

226.45 s.

Explanation:

Using Newton's fundamental equation,

F = ma Equation 1

Where F = force, m = mass of the freight train, a = acceleration of the freight train.

make a the subject of the equation,

a = F/m Equation 2

Given: F = 8.1×10⁵ N, m = 1.1×10⁷ kg

Substitute into equation 2

a = 8.1×10⁵/1.1×10⁷

a = 0.0736 m/s²

Using

a =(v-u)/t Equation 3

make t the subject of the equation

t = (v-u)/a Equation 4

Given: v = 60 km/h = 60(1000/3600) = 16.67 m/s, u = 0 m/s (from rest), a = 0.0736 m/s²

Substitute into equation 4

t = (16.67-0)/0.0736

t = 16.67/0.0736

t = 226.45 s.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2