The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. how long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? round to the nearest hundredth. the equation that represents the problem is 48 = 96t - 16t2. solve 16t2 - 96t + 48 = 0. complete the square to write 16t² - 96t + 48 = 0 as . solve (t - 3)² = 6. the arrow is at a height of 48 ft after approximately s and after s.