Find all pairs of real numbers $(x, y)$ such that $x + y = 6$ and $x^2 + y^2 = 28$. if you find more than one pair, then list your pairs in order by increasing $x$ value, separated by commas. for example, to enter the solutions $(2,4)$ and $(-3,9)$, you would enter "(-3,,4)" (without the quotation marks).

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

answer: what equations are there

step-by-step explanation: