Suppose josh drives the 45 miles from appleton to berwyn at the constant speed of 30 miles per hour. on the return trip, he drives from berwyn to appleton at the constant speed of 60 miles per hour. (a) what is josh’s average speed for the drive from appleton to berwyn and back? (b) what is the average of josh’s speeds driving from appleton to berwyn and from berwyn to appleton?

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this