Adrawer contains 3 tank tops, 6 short-sleeve shirts, 4 three-quarter sleeve shirts, and 5 long-sleeve shirts. what is the probability of randomly choosing a tank top and then a three-quarter sleeve length, if you replace the tank top?
a. 7/18
b. 1/27
c. 2/3
d. 1/18

The probability of  choosing a tank top and then a three-quarter sleeve length is:

                         1/27

The drawer contains:

3 tank tops, 6 short-sleeve shirts, 4 three-quarter sleeve shirts, and 5 long-sleeve shirts.

Now the drawing is done with replacement.

Hence, the drawing in the second chance is independent of drawing in the second chance.

Hence, we know that when two events A and B are independent then,

P(A∩B)=P(A)×P(B)

Hence,

P( choosing a tank top and then a three-quarter sleeve length) is:

P(choosing tank top)× P(choosing a three-quarter sleeve shirt)

= (3/18) × (4/18)

= 1/27

           Hence, the probability is:

                 Option: B   (1/27)

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1