Find 4 positive consecutive even integers such that the third times the fourth is twenty one times the first

Consecutive means in order, so like 1,2,3,4... or 14,15,16,17...

consecutive even means 2,4,6,...

now, first you define some variables

let "a1"  be the first positive even integer

well, you could define a2,a3,and a4 to be the next consecutive even integers but you actually dont need to
because the next consecutive even integer is
a1+2

the 3rd is
a1+2+2

and the 4th is
a1+2+2+2=a1+6

now, looking at the problem it states the "third" times the "fourth" is equal to 21 times the "first"

putting it into equation form

(a1+4)* (a1+6)= 21*a1

solve for a1, and then it should be easy to determine the rest of the positive consecutive even integers
 

1wthejjebehdn ejdjendnjdnendidne udhejhe djjenejejdjhv95 ag 55wo47wly4wl4uwo46qly4wlu4wly4wtieoyarpyrsou4spu46rsourso64so64so64so64o6raryoaours6oousrosuro6rso6sor6

What exactly is your question?