Which of the following shows the factors of 6x2 - 3x - 18?

6x^2 - 3x - 18
= 3(2x^2 - x - 6)
= 3(2x^2 - 4x + 3x - 6)
= 3[2x(x - 2) + 3( x - 2)]
= 3(x - 2)(2x + 3)

I hope this helped!!!

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*