The average person uses 6 square feet of area. If we have a 30 ft by 15 ft room with walls 10 ft high, approximately how many people could stand up in the room?

300persons

Step-by-step explanation:

First we need to find the total surface area of the room expressed as;

Total surface area = 2(LW+LH+WH)

L is the length = 30ft

W is the width = 15ft

H I the height = 10ft

Substitute

TSA = 2{(30(15)+30(10)+15(10)}

TSA = 2(450+300+150)

TSA = 2(900)

TSA = 1800ft²

Since an average person uses 6 square feet of area, the total numwr of people that can stand up the room is expressed as;

Total people = TSA/average area per person

Total person =1800/6

Total person = 300persons

Hence 300persos can stand up the room

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer:   y=2x-3

step-by-step explanation: