Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. which statements are true? check all that apply.
the radius of the circle is 3 units.
the center of the circle lies on the x-axis.
the center of the circle lies on the y-axis.
the standard form of the equation is (x – 1)² + y² = 3.
the radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

The answer is (A), (B) and (E).

Step-by-step explanation: The given equation of the circle is

We have

which is the standard form of the circle.

So, centre of the circle is (1, 0) and radius is 3 units.

Therefore, the centre lies on the X-axis.

Also, the radius of the circle is 3 units, which is same as the radius of our original circle.

Thus, options (A), (B) and (E) are correct.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.