Simplify 5 log2 k − 8 log2 m + 10 log2 n.
a. 7 log2 (k − m + n)
b. 7 log2 kn over m
c. log2 50 kn over 8 m
d. log2 k to the fifth power n to the tenth power/ m to the eighth power

The numerical coefficients of the logarithm are originally, the exponents of the variables. Such that,
                      log₂k⁵ - log₂m⁸ + log₂n¹⁰
Then the addition means we multiply them and subtraction means divide. The final answer would be,
                                       log (k⁵n¹⁰/m⁸)

25% increaseplus i think decrease i only know increase: ((