The distance of planet jupiter from the sun is approximately 7.8 ⋅ 108 kilometers, and the distance of planet saturn from the sun is 1.5 ⋅ 109 kilometers. about how many more kilometers is the distance of saturn from the sun than the distance of jupiter from the sun?
6.3 ⋅ 101 kilometers
6.3 ⋅ 108 kilometers
7.2 ⋅ 108 kilometers
7.2 ⋅ 109 kilometers

Step-by-step explanation:

The distance of planet Jupiter from the Sun is approximately 7.8 x 10⁸ kilometers.

Distance from Jupiter to Sun = 7.8 x 10⁸ kilometers

The distance of planet Saturn from the Sun is 1.5 x 10⁹ kilometers.

Distance from Saturn to Sun = 1.5 x 10⁹ kilometers

Difference in distances = 1.5 x 10⁹ - 7.8 x 10⁸ = 15 x 10⁸ - 7.8 x 10⁸

Difference in distances = 7.2 x 10⁸ kilometers

Option C is the correct answer,

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204