What is the equation of the line that passes through the point (6,-3) and has a
slope of – 3?

(6,-3) m=-3
formula is y=mx+c
substitute: -3= 3(6)+c
-3=-18+c (takeaway 18 from both sides)
-15=c

Rewrite equation in form y=mx+c

Therefore answer is y=-3x-15

I think this is how u do it from what I can remember :)