Use trigonometric substitution to verify that

∫0xa2−t2√dt
〖√(a^2-t^2 ) dt〗=1/2 a^2 sin^(-1)⁡〖x/a〗+1/2 x√(a^2-x^2 )

use the figure to give trigonometric interpretations of both terms on the right side of the equation in part (a).

just keep asking questions until you have a better understanding.

step-by-step explanation:

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.