The point P(6, –1) is translated according to the rule (x, y) → (x – 5, y – 2). What are the coordinates of P'? P'(1, 2) P'(1, 1) P'(1, –3) P'(4, 4)

(1, -3)

Step-by-step explanation:

If the point P(6, –1) is translated according to the rule (x, y) → (x – 5, y – 2).

To get the coordinate of P', we will replace x as 6 and y as -1 in the translation given as shown

Coordinate of P' = (6 -5, -1, -2)

Coordinate of P' = (1, -3)

hence the coordinate of P' is (1, -3)

p'(1 -3)

Step-by-step explanation: