Consider the figure below with circles R, C, and D below, where circle R and circle D are congruent. If RA = 42 and CE = 32, then answer the questions below.
R
D
424
E
32
с
Part A: Determine CA + ED.
Part B: Determine the combined circumference of all three circles.

a) CA + ED = 74

Step-by-step explanation:

The complete question is attached in the image

Solution

Here the two circles R and D are congruent and thus their radius will be equal  

Hence, RA (radius of circle R ) = DE (radius of circle D)

Hence, CA + ED = CA + 42

Also, RC = CD  

CA = CE + RA  = 32

So, CA + EO = 32 +42 = 74  

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true