DOES ANYONE UNDERSTAND QUADRATIC APPLICATIONS FOR ALGEBRA 1? PLS DONT RESOND IF YOU DINT KNOW

1 ) Vertex form.

2 ) Standard form.

3 ) I'm not sure about this one, but there are only 3 forms, in which the last one is factored form, and the other two are above, so it must be factored form.

Step-by-step explanation:

1 ) Vertex form : y = a( x - h )² + k

Vertex form shows you where the vertex(the lowest/highest point aka ( h, k ) ) of the parabola is, without graphing it. (But you could graph it and find the vertex like that, I recommend you use desmos graphing)

2 )Standard form : y = ax² + bx + c

Standard form can be used to show the y-intercept( aka c ), in this case, where the snowball was thrown from. (Again, you can graph it and find where he parabola hits the y axis)

3 ) Factored form : ( ax + c )( bx + d )

Factored form tells us the x-intercepts, or in this case where the snowball landed or how long the snowball is in the air. (like i said, you could graph it, and find the points(there could be only one or maybe none in some cases) that are on the x axis)

I know this was four days ago, but I hope this helped you understand a little better.

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)