Data from a representative sample were used to estimate that 31% of all computer users in a recent year had tried to get on a Wi-Fi network that was not their own in order to save money. You decide to conduct a survey to estimate this proportion for the current year. What is the required sample size if you want to estimate this proportion with a margin of error of 0.05

The required sample size is 329.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is:

31% of all computer users in a recent year had tried to get on a Wi-Fi network that was not their own in order to save money.

This means that

Confidence level is not given, so we assume 95%.

95% confidence level

So , z is the value of Z that has a pvalue of , so .

What is the required sample size if you want to estimate this proportion with a margin of error of 0.05?

We need a sample size of n. n is found when M = 0.05. So

Rounding up

The required sample size is 329.

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step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right