Use the x method to find the solutions of 6x2 + 2x – 20 = 0. x = x =

To get the solution of the quadratic equation we factorize it as follows:
6x^2+2x-20=0
factoring the above we get:
6x^2-10x+12x-20=0
2x(3x-5)+4(3x-5)=0
(2x+4)(3x-5)=0
hence the root are:
(2x+4) and (3x-5)
thus the zeros are:
2x+4=0
x=-2
3x-5=0
3x=5
x=5/3
hence the answer is x=-2 or x=5/3

The solutions of the given quadratic equations is 5/3 and -2

Given the quadratic function expressed as:

6x^2 + 2x – 20 = 0

Factorizing the function we will have:

6x^2 + 2x – 20 = 0

3x^2 + x - 10 = 0

3x^2 +6x - 5x - 10 = 0

3x(x+2)  5(x+2) = 0

Group the function;

(3x-5)(x+2) = 0

Find the factors

3x- 5 = 0 and x + 2 = 0

x = 5/3 and -2

The solutions of the given quadratic equations is 5/3 and -2

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Siciuenckwk the answer

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!