Let y = x² In(x).
dy/dx the lesson is differentiate products​

dy/dx = x(1+2lnx)

Step-by-step explanation:

Given y = x² In(x).

dy/dx = Udv/dx + Vdu/dx

Let U = x², V = lnx

du/dx = 2x

dv/dx = 1/x

Substitute into the formula;

dy/dx = x²(1/x) + lnx(2x)

dy/dx = x + 2xlnx

dy/dx = x(1+2lnx)

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!