In ΔHIJ, the measure of ∠j=33cm,∠H=148°and I= 21°Find the length of i to the nearest tenth of a centimeter

i = 62 cm

Step-by-step explanation:

I have drawn the triangle to reflect the angles and dimension given and attached it.

The missing angle in the triangle is ∠J.

we know that sum of angles in a triangle = 180°

Thus;

148 + 21 + ∠J = 180

∠J = 180 - 148 - 21

∠J = 11°

To find i, we will make use of sine rule which is; a/sin A = b/sin B = c/sin C

Thus;

i/sin I = j/sin J

i = j sin I/sin J

i = (33 × sin 21)/sin 11

i = 61. 979 cm

To the nearest tenth gives;

i = 62 cm

idk

step-by-step explanation:

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: