Jack and Jill went for a walk separately. Jack’s total distance in blocks, x, was thirty blocks fewer than twice Jill’s total distance in blocks, y. The difference between five times Jack’s total distance and twice Jill’s total distance is ten blocks. The following system can be used to model this relationship.

x= 2y -30

5x-2y=10

Step-by-step explanation:

substitute x= 2y-30 into the 2nd equation

5(2y-30)-2y = 10

10y-150-2y=10

10y -150-2y= 10

8y-150=10

  +150     +150

8y= 160 so y =20   substitute y=20 into x=2y-30 so 40-30=10 so x=10 & y=20

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: