A box of jerseys for a pick-up game of basketball contains 10 extra-large jerseys, 6 large jerseys, and 4 medium Jerseys. If you are first to the box and grab 2 jerseys, what is the probability that you randomly grab 2 medium jerseys? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.​

3/95

Total Number of jerseys:

10+6+4=20

Odds of first jersey being medium:

4/20

Odds of second jersey being medium

3/19

(4/20)*(3/19)=12/380=

6/190=3/95

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2