The Kato family takes out a $30,000 home improvement loan. The loan has an annual interest rate of 6.5%. If the loan is paid back over 12 years instead of 10 years, how
much more interest will they pay?

$3900

Step-by-step explanation:

Given data

P= $30,000

r= 6.5%

t= 10 years

t= 12 years

Let us find the SI interest after 10 years

SI= PRT/100

SI= 30000*6.5*10/100

SI= 1950000/100

SI= 19500

Let us find the SI interest after 12 years

SI= PRT/100

SI= 30000*6.5*12/100

SI= 2340000/100

SI= 23400

The extra amount paid is

=23400- 19500

=$3900

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )